What are the types of chemical equilibrium?

There are two types of chemical equilibrium:

(i) Homogeneous equilibrium: It is that equilibrium reaction in which all the reactants and products are in the same phase. For example



(ii) Heterogeneous equilibrium: It is that equilibrium reaction in which reactants and products are present in two or more phases, e.g. 


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Write the equilibrium constant expression for the following reactions:
left parenthesis straight i right parenthesis space BaCO subscript 3 left parenthesis straight s right parenthesis space space rightwards harpoon over leftwards harpoon space space space space BaO left parenthesis straight s right parenthesis space plus space CO subscript 2 left parenthesis straight g right parenthesis
left parenthesis ii right parenthesis space AgBr left parenthesis straight s right parenthesis space space rightwards harpoon over leftwards harpoon space space space Ag to the power of plus left parenthesis aq right parenthesis space plus space Br to the power of minus left parenthesis aq right parenthesis
left parenthesis iii right parenthesis space Al left parenthesis straight s right parenthesis plus space 3 straight H to the power of plus left parenthesis aq right parenthesis space space space rightwards harpoon over leftwards harpoon space space space space Al to the power of 3 plus end exponent left parenthesis aq right parenthesis space plus space 3 over 2 straight H subscript 2 left parenthesis straight g right parenthesis




By convention, 

Hence  

By convention, 

  

For gases, using partial pressures,


By convention,    







By convention, 

Hence 
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State and explain Le-Chatelier’s principle.


Le-Chatelier’s principle. This principle may be stated as if a stress (such as a change in concentration, temperature or pressure) is applied to a system in equilibrium, the equilibrium shifts in a way to undo or nullify the effect of the imposed stress.

(i) Effect of change of concentration on equilibrium. If the concentration of any one or all the reactants is increased, the equilibrium shifts towards right hand side to form more products whereas increase in the concentration of any one or all the products shifts the equilibrium towards left hand side to form more reactants in order to nullify the effect of increase in the concentration of reactants or products respectively. For example, consider the reaction,


Increase in concentration of reactants (N2, H2) will shift the equilibrium in the forward direction in order to decrease their concentration. The addition of extra NH3 from outside the equilibrium mixture will shift the equilibrium in the backward direction.

(ii) Effect of temperature on equilibrium. According to Le-Chatelier’s principle of increasing the temperature, the equilibrium shifts towards that direction where absorption of heat (endothermic change) takes place in order to nullify the effect of the rise in temperature. On the other hand, on decreasing the temperature, the equilibrium shifts towards that direction where the evolution of heat (exothermic change) takes place in order to nullify the effect of a decrease in temperature. For example.
   

On decreasing the temperature, the equilibrium shifts in the forward direction i.e. towards the exothermic reaction (evolution of heat). Thus, a decrease in temperature favours the formation of sulphur trioxide.


On increasing the temperature, the equilibrium shifts in the forward direction i.e. towards the endothermic reaction (absorption of heat). Thus, an increase in the temperature favours the formation of nitric oxide.

(iii) Effect of change in pressure on equilibrium. On increasing the pressure, the number of moles per unit volume increases and thus according to Le-Chatelier’s principle the equilibrium shifts towards the side where the number of moles per unit volume decreases in order to nullify the effect of an increase in pressure. For example.

On increasing the pressure, the number of moles per unit volume increases and thus according to Le-Chaterlier's principle the equilibrium shifts towards the right-hand side (i.e. towards the formation of ammonia) where the number of moles per unit volume decreases.
(iv) Effect of the catalyst. A catalyst has no effect on equilibrium point. This is because it increases the rate of the forward as well as backward reaction to the same extent. Thus, a catalyst does not affect the position of equilibrium, but simply helps to achieve the equilibrium in a shorter time i.e. quickly.

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What is the effect of adding an inert gas(say He or N2):
(i) at constant volume and
(ii) at the constant pressure on the following equilibrium:
PCl subscript 5 left parenthesis straight g right parenthesis space space rightwards harpoon over leftwards harpoon space space space space PCl subscript 3 left parenthesis straight g right parenthesis space plus space Cl subscript 2 left parenthesis straight g right parenthesis
 


The given dissociation equilibrium is

   

           

(i) Adding inert gas at constant volume. If an inert gas like helium or nitrogen etc. is added to a system at equilibrium at constant volume, then the total pressure increases. However, there will be no change in the position of equilibrium, even though the pressure has changed. This is because the concentrations of reactants and products (number of moles/volume) will not change. Hence the values of concentrations will continue to satisfy the equilibrium law. Hence the state of equilibrium will remain unaffected.

(ii) Adding inert gas at constant pressure. When an inert gas is added to a system at equilibrium keeping the pressure constant, the volume of the system increases. This results in a decrease in a number of moles of reactants per unit volume. According to Le-Chatelier’s principle, the equilibrium shifts in a direction in which there is an increase in the number of moles of gases. Hence the equilibrium shifts towards the forward direction where the number of moles of gases increases. In other words, more PCldissociates to give PCl3 and Cl2. Hence dissociation of PCl5 increases with the addition of an inert gas.

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With the help of Le-Chatelier’s principle, determine the favourable conditions of concentration, temperature and pressure for the reaction
straight N subscript 2 left parenthesis straight g right parenthesis space plus space 3 straight H subscript 2 left parenthesis straight g right parenthesis space space rightwards harpoon over leftwards harpoon space space space space 2 NH subscript 3 left parenthesis straight g right parenthesis semicolon space space increment subscript straight r straight H to the power of 0 space equals space minus 93.6 space kJ






(i) Effect of concentration. Increase in concentration of reactants (N2, H2) will shift the equilibrium in the forward direction to form more ammonia in order to decrease their concentrations. The addition of extra NH3 from outside to the equilibrium mixture will shift the equilibrium in the backward direction. Thus, the addition of N2 and H2 favours the formation of ammonia.

(ii) Effect of temperature. The forward reaction is exothermic in nature while the backward reaction is endothermic in nature. According to Le-Chatelier’s principle, on decreasing the temperature, the equilibrium shifts towards that direction where the evolution of heat takes place in order to nullify the effect of decreasing temperature. Thus, a decrease in temperature favours the formation of ammonia.
On the other hand, on increasing the temperature the equilibrium shifts towards the backward direction where absorption of heat takes place in order to nullify the effect of the rise in temperature. Thus, lower temperature favours the formation of ammonia.

(iii) Effect of pressure. On increasing the pressure, the number of moles per unit volume increases and thus according to Le-Chatelier’s principle, the equilibrium shifts towards that side where the number of moles per unit volume decreases in order to nullify the effect of an increase in pressure. On the other hand, on decreasing the pressure, the equilibrium shifts towards the backwards direction i.e. ammonia decomposes to give N2 and H2. Thus, an increase in pressure favours the formation of ammonia.
Hence favourable conditions in the formation of ammonia are:

(i) The addition of N2 and H2 
(ii) Lower temperature
(iii) Higher pressure.

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